1. Thirty men can complete a work in 36 days. In how many days can 18 men complete the same piece of work?
(1) 48
(2) 36
(3) 60
2. Gaurav spends 50% of his monthly income on household items, 20% of his monthly income on buying clothes, 5% of his monthly income on medicines and saves remaining Rs. 11,250 . What is Gaurav’s monthly income?
(1) Rs. 38,200
(2) Rs. 34,000
(3) Rs. 41,600
(4) Rs. 45,000
3. The number obtained by interchanging the two digits of a two digit number is lesser than the original number by 54. If the sum of the two digits of the number is 12, then what is the original number?
(1) 28
(2) 39
(3) 93
(4) Can’t say
4. At present Ayushi is eight times her daughter’s age. Eight years from now, the ratio of the ages of Ayushi and her daughter will be 10 : 3 respectively. What is Ayushi’s present age ?
(1) 32 years
(2) 40 years
(3) 36 years
(4) Can’t say
5. In how many different ways can 4 boys and 3 girls be arranged in a row such that all the boys stand together and all the girls stand together?
(1) 75
(2) 576
(3) 288
(4) 24
6. X can do a piece of work in 20 days and Y can do it in 10 days. They started together, but after 6 days X leaves off. Y will do the rest work in
(1) 1 day
(2) 2 days
(3) 7/3 days
(4) 3 days
7. A radio is sold for Rs 990 at a profit of 10%. What would have been the gain or loss in percentage had it been sold for Rs 880?
(1) 19/3% gain
(2) 17/3% loss
(3) 17% gain
(4) 20/9% loss
8. In an exam, 60% of the total student passed. If the number of failed students is 320 then the total number of students is
(1)600
(2)700
(3)800
(4)900
9. A cycle is bought for Rs 840 and sold at Rs 920. What is the percentage gain
(1)10.50%
(2)8.52%
(3)7.35%
(4)9.52%
10. If sandeep salary is 30% more than Amar’s salary, the how many percent is Amar’s salary less than that of Sandeep’s?
(1)56%
(2)23.07%
(3) 50/3%
(4)50.6%
Answers
1. (3)
Required number of days = (30 * 36)/18 = 60
2. (4)
Let total income of Gaurav be x. Then
(100 – 50 – 20 – 5)% of x = 11250
x = 45000.
3. (3)
Let the number be xy
(10x + y) – (10y + x) = 54
x – y = 6 And x + y = 12
Solving the equations we get x = 9 and y = 3
So the number is 93.
Required number of days = (30 * 36)/18 = 60
2. (4)
Let total income of Gaurav be x. Then
(100 – 50 – 20 – 5)% of x = 11250
x = 45000.
3. (3)
Let the number be xy
(10x + y) – (10y + x) = 54
x – y = 6 And x + y = 12
Solving the equations we get x = 9 and y = 3
So the number is 93.
4. (1)
Let the age of Ayushi’s daughter be x. Then Ayushi’s age is 8x.
(8x + 8)/ (x + 8) = 10/3
x = 4
Ayushi present age = 8x = 32 years.
5. (3)
Required number of ways = 4! * 3! * 2! = 288.
6. 1
(X + Y)’s 6 days’ work = 6 * (1/20 + 1/10) = 9/10
Remaining work = 1 - 9/10 = 1/10
1/10 work is done 2y Y in 10 * 1/10 = 1 day
7. 4
Let the CP is Rs x.
Then, x * 110/100 = 990
x = 900
Now CP is Rs 900 and SP is 880.
% loss = 20/900 * 100 = 20/9%
8. 3
Let the number of student is x out of that 40% have failed.
40/100 * x = 320
x = 320 * 100/40 = 800
9. 4
CP = Rs 840 and SP = Rs 920
Gain = 920 – 840 = Rs 80
gain percentage = 80/840 * 100 = 9.52%
10. 2;
Amar’s salary is less than of Sandeep 2y
(R/100 + R * 100)% = (30/(100 + 30) * 100)%
(30/130 *100 )% = 300/13% = 23% APPROX
